LeetCode 455. Assign Cookies
Assume you are an awesome parent and want to give your children some cookies. But, you should give each child at most one cookie.
Each child i has a greed factor g[i]
, which is the minimum size of a cookie that the child will be content with; and each cookie j
has a size s[j]
. If s[j] >= g[i]
, we can assign the cookie j
to the child i
, and the child i
will be content. Your goal is to maximize the number of your content children and output the maximum number.
Example 1:
Input: g = [1,2,3], s = [1,1]
Output: 1
Explanation: You have 3 children and 2 cookies. The greed factors of 3 children are 1, 2, 3.
And even though you have 2 cookies, since their size is both 1, you could only make the child whose greed factor is 1 content.
You need to output 1.
method: 贪心
先排序
从大往小遍历,用大的饼干先去满足大的需求
int findContentChildren(vector<int>& g, vector<int>& s) {
sort(g.begin(), g.end());
sort(s.begin(), s.end());
int res = 0;
int index = s.size() - 1; // 用index遍历就不需要嵌套for
for (int i = g.size() - 1; i >= 0; i--) {
if (index >= 0 && s[index] >= g[i]) {
index--;
res++;
}
}
return res;
}
也可以从小往大遍历,用小的饼干先去满足小的需求
int findContentChildren(vector<int>& g, vector<int>& s) {
sort(g.begin(), g.end());
sort(s.begin(), s.end());
int index = 0;
for (int i = 0; i < s.size(); i++) {
if (index < g.size() && g[index] <= s[i]) {
index++;
}
}
return index; // 有几个被满足了就是结果
}