LeetCode 279. Perfect Squares
Given an integer n
, return the least number of perfect square numbers that sum to n.
A perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, 1
, 4
, 9
, and 16
are perfect squares while 3
and 11
are not.
Example 1:
Input: n = 12
Output: 3
Explanation: 12 = 4 + 4 + 4.
Example 2:
Input: n = 13
Output: 2
Explanation: 13 = 4 + 9.
method: 完全背包
dp[i]
:组成整数i
需要的最少的完全平方数个数为dp[i]
物品:完全平方数
因为要最小,所以初始化为INT_MAX
来一个j
,就可以考虑把整数i拆成j*j
和i-j*j
两部分
求最少数量
递推公式:dp[i] = min(dp[i], dp[i-j*j]+1)
int numSquares(int n) {
vector<int> dp(n + 1, INT_MAX);
dp[0] = 0;
for (int i = 1; i <= n; i++) { // 遍历背包(整数x)
for (int j = 1; j * j <= i; j++) { // 遍历物品(平方数),必须小于等于
dp[i] = min(dp[i], dp[i - j * j] + 1);
}
}
return dp[n];
}
刚好j*j==i
,说明i
本身就是完全平方数,所以组成个数dp[i]=dp[0]+1
,所以dp[0]
必须初始化为0